2x^2+8+1x=0

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Solution for 2x^2+8+1x=0 equation: 



2x^2+8+1x=0

We add all the numbers together, and all the variables

2x^2+x+8=0

a = 2; b = 1; c = +8;
Δ = b2-4ac
Δ = 12-4·2·8
Δ = -63
Delta is less than zero, so there is no solution for the equation

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